2(x-5)(x+5)=0

Solution for 2(x-5)(x+5)=0 equation:

Simplifying
2(x + -5)(x + 5) = 0

Reorder the terms:
2(-5 + x)(x + 5) = 0

Reorder the terms:
2(-5 + x)(5 + x) = 0

Multiply (-5 + x) * (5 + x)
2(-5(5 + x) + x(5 + x)) = 0
2((5 * -5 + x * -5) + x(5 + x)) = 0
2((-25 + -5x) + x(5 + x)) = 0
2(-25 + -5x + (5 * x + x * x)) = 0
2(-25 + -5x + (5x + x2)) = 0

Combine like terms: -5x + 5x = 0
2(-25 + 0 + x2) = 0
2(-25 + x2) = 0
(-25 * 2 + x2 * 2) = 0
(-50 + 2x2) = 0

Solving
-50 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 2x2 = 0 + 50

Combine like terms: -50 + 50 = 0
0 + 2x2 = 0 + 50
2x2 = 0 + 50

Combine like terms: 0 + 50 = 50
2x2 = 50

Divide each side by '2'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}