2(x-5)+(x-2)=8+7(x-4)

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Solution for 2(x-5)+(x-2)=8+7(x-4) equation: 



2(x-5)+(x-2)=8+7(x-4)

We move all terms to the left:

2(x-5)+(x-2)-(8+7(x-4))=0

We multiply parentheses

2x+(x-2)-(8+7(x-4))-10=0

We get rid of parentheses

2x+x-(8+7(x-4))-2-10=0



We calculate terms in parentheses: -(8+7(x-4)), so:

8+7(x-4)

determiningTheFunctionDomain
7(x-4)+8

We multiply parentheses

7x-28+8

We add all the numbers together, and all the variables

7x-20

Back to the equation:

-(7x-20)



We add all the numbers together, and all the variables

3x-(7x-20)-12=0

We get rid of parentheses

3x-7x+20-12=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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