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2(x-5)+1=3(2x+1)
We move all terms to the left:
2(x-5)+1-(3(2x+1))=0
We multiply parentheses
2x-(3(2x+1))-10+1=0
We calculate terms in parentheses: -(3(2x+1)), so:We add all the numbers together, and all the variables
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
2x-(6x+3)-9=0
We get rid of parentheses
2x-6x-3-9=0
We add all the numbers together, and all the variables
-4x-12=0
We move all terms containing x to the left, all other terms to the right
-4x=12
x=12/-4
x=-3
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