2(x-5)+2=3(x+2)

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Solution for 2(x-5)+2=3(x+2) equation: 



2(x-5)+2=3(x+2)

We move all terms to the left:

2(x-5)+2-(3(x+2))=0

We multiply parentheses

2x-(3(x+2))-10+2=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

2x-(3x+6)-8=0

We get rid of parentheses

2x-3x-6-8=0

We add all the numbers together, and all the variables

-1x-14=0

We move all terms containing x to the left, all other terms to the right

-x=14

x=14/-1

x=-14

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