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2(x-5)+4=3(x+2)-5
We move all terms to the left:
2(x-5)+4-(3(x+2)-5)=0
We multiply parentheses
2x-(3(x+2)-5)-10+4=0
We calculate terms in parentheses: -(3(x+2)-5), so:We add all the numbers together, and all the variables
3(x+2)-5
We multiply parentheses
3x+6-5
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
2x-(3x+1)-6=0
We get rid of parentheses
2x-3x-1-6=0
We add all the numbers together, and all the variables
-1x-7=0
We move all terms containing x to the left, all other terms to the right
-x=7
x=7/-1
x=-7
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