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2(x-5)+6=4x-2(4+x)
We move all terms to the left:
2(x-5)+6-(4x-2(4+x))=0
We add all the numbers together, and all the variables
2(x-5)-(4x-2(x+4))+6=0
We multiply parentheses
2x-(4x-2(x+4))-10+6=0
We calculate terms in parentheses: -(4x-2(x+4)), so:We add all the numbers together, and all the variables
4x-2(x+4)
We multiply parentheses
4x-2x-8
We add all the numbers together, and all the variables
2x-8
Back to the equation:
-(2x-8)
2x-(2x-8)-4=0
We get rid of parentheses
2x-2x+8-4=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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