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2(x-5)+6x=-4(x-6)+2
We move all terms to the left:
2(x-5)+6x-(-4(x-6)+2)=0
We add all the numbers together, and all the variables
6x+2(x-5)-(-4(x-6)+2)=0
We multiply parentheses
6x+2x-(-4(x-6)+2)-10=0
We calculate terms in parentheses: -(-4(x-6)+2), so:We add all the numbers together, and all the variables
-4(x-6)+2
We multiply parentheses
-4x+24+2
We add all the numbers together, and all the variables
-4x+26
Back to the equation:
-(-4x+26)
8x-(-4x+26)-10=0
We get rid of parentheses
8x+4x-26-10=0
We add all the numbers together, and all the variables
12x-36=0
We move all terms containing x to the left, all other terms to the right
12x=36
x=36/12
x=3
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