2(x-5)+8x+4=1/2(6x-2)

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Solution for 2(x-5)+8x+4=1/2(6x-2) equation: 



2(x-5)+8x+4=1/2(6x-2)

We move all terms to the left:

2(x-5)+8x+4-(1/2(6x-2))=0



Domain of the equation: 2(6x-2))!=0

x∈R



We add all the numbers together, and all the variables

8x+2(x-5)-(1/2(6x-2))+4=0

We multiply parentheses

8x+2x-(1/2(6x-2))-10+4=0

We multiply all the terms by the denominator


8x*2(6x-2))+2x*2(6x-2))-(1-10*2(6x-2))+4*2(6x-2))=0

Wy multiply elements

32x^3(6-2))-(1-10*2(6x-2))+4*2(6x-2))=0

We do not support expression: x^3(6

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