2(x-5)+x=3(x-4)+2

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Solution for 2(x-5)+x=3(x-4)+2 equation: 


Simplifying
2(x + -5) + x = 3(x + -4) + 2

Reorder the terms:
2(-5 + x) + x = 3(x + -4) + 2
(-5 * 2 + x * 2) + x = 3(x + -4) + 2
(-10 + 2x) + x = 3(x + -4) + 2

Combine like terms: 2x + x = 3x
-10 + 3x = 3(x + -4) + 2

Reorder the terms:
-10 + 3x = 3(-4 + x) + 2
-10 + 3x = (-4 * 3 + x * 3) + 2
-10 + 3x = (-12 + 3x) + 2

Reorder the terms:
-10 + 3x = -12 + 2 + 3x

Combine like terms: -12 + 2 = -10
-10 + 3x = -10 + 3x

Add '10' to each side of the equation.
-10 + 10 + 3x = -10 + 10 + 3x

Combine like terms: -10 + 10 = 0
0 + 3x = -10 + 10 + 3x
3x = -10 + 10 + 3x

Combine like terms: -10 + 10 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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