2(x-5)-2=3(x+10)

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Solution for 2(x-5)-2=3(x+10) equation: 



2(x-5)-2=3(x+10)

We move all terms to the left:

2(x-5)-2-(3(x+10))=0

We multiply parentheses

2x-(3(x+10))-10-2=0



We calculate terms in parentheses: -(3(x+10)), so:

3(x+10)

We multiply parentheses

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

2x-(3x+30)-12=0

We get rid of parentheses

2x-3x-30-12=0

We add all the numbers together, and all the variables

-1x-42=0

We move all terms containing x to the left, all other terms to the right

-x=42

x=42/-1

x=-42

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