2(x-5)-5(x-2)=x+4-(-2)

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Solution for 2(x-5)-5(x-2)=x+4-(-2) equation: 



2(x-5)-5(x-2)=x+4-(-2)

We move all terms to the left:

2(x-5)-5(x-2)-(x+4-(-2))=0

We multiply parentheses

2x-5x-(x+4-(-2))-10+10=0



We calculate terms in parentheses: -(x+4-(-2)), so:

x+4-(-2)

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

-3x-(x+6)=0

We get rid of parentheses

-3x-x-6=0

We add all the numbers together, and all the variables

-4x-6=0

We move all terms containing x to the left, all other terms to the right

-4x=6

x=6/-4

x=-1+1/2

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