2(x-5)-5(x-2)=x+4-(x-2)

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Solution for 2(x-5)-5(x-2)=x+4-(x-2) equation: 



2(x-5)-5(x-2)=x+4-(x-2)

We move all terms to the left:

2(x-5)-5(x-2)-(x+4-(x-2))=0

We multiply parentheses

2x-5x-(x+4-(x-2))-10+10=0



We calculate terms in parentheses: -(x+4-(x-2)), so:

x+4-(x-2)

determiningTheFunctionDomain
x-(x-2)+4

We get rid of parentheses

x-x+2+4

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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