2(x-5)-5(x-2)=x+7-(x-8)

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Solution for 2(x-5)-5(x-2)=x+7-(x-8) equation: 



2(x-5)-5(x-2)=x+7-(x-8)

We move all terms to the left:

2(x-5)-5(x-2)-(x+7-(x-8))=0

We multiply parentheses

2x-5x-(x+7-(x-8))-10+10=0



We calculate terms in parentheses: -(x+7-(x-8)), so:

x+7-(x-8)

determiningTheFunctionDomain
x-(x-8)+7

We get rid of parentheses

x-x+8+7

We add all the numbers together, and all the variables

15

Back to the equation:

-(15)



We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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