2(x-5)=10+4(x-10)

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Solution for 2(x-5)=10+4(x-10) equation: 



2(x-5)=10+4(x-10)

We move all terms to the left:

2(x-5)-(10+4(x-10))=0

We multiply parentheses

2x-(10+4(x-10))-10=0



We calculate terms in parentheses: -(10+4(x-10)), so:

10+4(x-10)

determiningTheFunctionDomain
4(x-10)+10

We multiply parentheses

4x-40+10

We add all the numbers together, and all the variables

4x-30

Back to the equation:

-(4x-30)



We get rid of parentheses

2x-4x+30-10=0

We add all the numbers together, and all the variables

-2x+20=0

We move all terms containing x to the left, all other terms to the right

-2x=-20

x=-20/-2

x=+10

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