2(x-5)=2(x-4)2

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Solution for 2(x-5)=2(x-4)2 equation: 



2(x-5)=2(x-4)2

We move all terms to the left:

2(x-5)-(2(x-4)2)=0

We multiply parentheses

2x-(2(x-4)2)-10=0



We calculate terms in parentheses: -(2(x-4)2), so:

2(x-4)2

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

2x-4x+16-10=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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