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2(x-5)=3(4x+10)
We move all terms to the left:
2(x-5)-(3(4x+10))=0
We multiply parentheses
2x-(3(4x+10))-10=0
We calculate terms in parentheses: -(3(4x+10)), so:We get rid of parentheses
3(4x+10)
We multiply parentheses
12x+30
Back to the equation:
-(12x+30)
2x-12x-30-10=0
We add all the numbers together, and all the variables
-10x-40=0
We move all terms containing x to the left, all other terms to the right
-10x=40
x=40/-10
x=-4
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