2(x-5)=3(x+2)+2(x-1)=59

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Solution for 2(x-5)=3(x+2)+2(x-1)=59 equation: 



2(x-5)=3(x+2)+2(x-1)=59

We move all terms to the left:

2(x-5)-(3(x+2)+2(x-1))=0

We multiply parentheses

2x-(3(x+2)+2(x-1))-10=0



We calculate terms in parentheses: -(3(x+2)+2(x-1)), so:

3(x+2)+2(x-1)

We multiply parentheses

3x+2x+6-2

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

2x-5x-4-10=0

We add all the numbers together, and all the variables

-3x-14=0

We move all terms containing x to the left, all other terms to the right

-3x=14

x=14/-3

x=-4+2/3

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