2(x-5)=3(x+2)-4(x-2)

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Solution for 2(x-5)=3(x+2)-4(x-2) equation:



2(x-5)=3(x+2)-4(x-2)
We move all terms to the left:
2(x-5)-(3(x+2)-4(x-2))=0
We multiply parentheses
2x-(3(x+2)-4(x-2))-10=0
We calculate terms in parentheses: -(3(x+2)-4(x-2)), so:
3(x+2)-4(x-2)
We multiply parentheses
3x-4x+6+8
We add all the numbers together, and all the variables
-1x+14
Back to the equation:
-(-1x+14)
We get rid of parentheses
2x+1x-14-10=0
We add all the numbers together, and all the variables
3x-24=0
We move all terms containing x to the left, all other terms to the right
3x=24
x=24/3
x=8

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