2(x-5)=3(x+2)-4(x-2)

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Solution for 2(x-5)=3(x+2)-4(x-2) equation: 



2(x-5)=3(x+2)-4(x-2)

We move all terms to the left:

2(x-5)-(3(x+2)-4(x-2))=0

We multiply parentheses

2x-(3(x+2)-4(x-2))-10=0



We calculate terms in parentheses: -(3(x+2)-4(x-2)), so:

3(x+2)-4(x-2)

We multiply parentheses

3x-4x+6+8

We add all the numbers together, and all the variables

-1x+14

Back to the equation:

-(-1x+14)



We get rid of parentheses

2x+1x-14-10=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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