2(x-5)=3(x-2)-4(x-2)

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Solution for 2(x-5)=3(x-2)-4(x-2) equation: 



2(x-5)=3(x-2)-4(x-2)

We move all terms to the left:

2(x-5)-(3(x-2)-4(x-2))=0

We multiply parentheses

2x-(3(x-2)-4(x-2))-10=0



We calculate terms in parentheses: -(3(x-2)-4(x-2)), so:

3(x-2)-4(x-2)

We multiply parentheses

3x-4x-6+8

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We get rid of parentheses

2x+1x-2-10=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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