2(x-5)=42-3(x+4)

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Solution for 2(x-5)=42-3(x+4) equation: 



2(x-5)=42-3(x+4)

We move all terms to the left:

2(x-5)-(42-3(x+4))=0

We multiply parentheses

2x-(42-3(x+4))-10=0



We calculate terms in parentheses: -(42-3(x+4)), so:

42-3(x+4)

determiningTheFunctionDomain
-3(x+4)+42

We multiply parentheses

-3x-12+42

We add all the numbers together, and all the variables

-3x+30

Back to the equation:

-(-3x+30)



We get rid of parentheses

2x+3x-30-10=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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