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2(x-5)=4x-(10-2x)
We move all terms to the left:
2(x-5)-(4x-(10-2x))=0
We add all the numbers together, and all the variables
2(x-5)-(4x-(-2x+10))=0
We multiply parentheses
2x-(4x-(-2x+10))-10=0
We calculate terms in parentheses: -(4x-(-2x+10)), so:We get rid of parentheses
4x-(-2x+10)
We get rid of parentheses
4x+2x-10
We add all the numbers together, and all the variables
6x-10
Back to the equation:
-(6x-10)
2x-6x+10-10=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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