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2(x-5)=5(2x+1)+1
We move all terms to the left:
2(x-5)-(5(2x+1)+1)=0
We multiply parentheses
2x-(5(2x+1)+1)-10=0
We calculate terms in parentheses: -(5(2x+1)+1), so:We get rid of parentheses
5(2x+1)+1
We multiply parentheses
10x+5+1
We add all the numbers together, and all the variables
10x+6
Back to the equation:
-(10x+6)
2x-10x-6-10=0
We add all the numbers together, and all the variables
-8x-16=0
We move all terms containing x to the left, all other terms to the right
-8x=16
x=16/-8
x=-2
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