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2(x-5)=5(3-2x)-1
We move all terms to the left:
2(x-5)-(5(3-2x)-1)=0
We add all the numbers together, and all the variables
2(x-5)-(5(-2x+3)-1)=0
We multiply parentheses
2x-(5(-2x+3)-1)-10=0
We calculate terms in parentheses: -(5(-2x+3)-1), so:We get rid of parentheses
5(-2x+3)-1
We multiply parentheses
-10x+15-1
We add all the numbers together, and all the variables
-10x+14
Back to the equation:
-(-10x+14)
2x+10x-14-10=0
We add all the numbers together, and all the variables
12x-24=0
We move all terms containing x to the left, all other terms to the right
12x=24
x=24/12
x=2
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