2(x-5)=7-5(2x+1)

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Solution for 2(x-5)=7-5(2x+1) equation: 



2(x-5)=7-5(2x+1)

We move all terms to the left:

2(x-5)-(7-5(2x+1))=0

We multiply parentheses

2x-(7-5(2x+1))-10=0



We calculate terms in parentheses: -(7-5(2x+1)), so:

7-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+7

We multiply parentheses

-10x-5+7

We add all the numbers together, and all the variables

-10x+2

Back to the equation:

-(-10x+2)



We get rid of parentheses

2x+10x-2-10=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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