2(x-5)=7-5(2x+11)

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Solution for 2(x-5)=7-5(2x+11) equation: 



2(x-5)=7-5(2x+11)

We move all terms to the left:

2(x-5)-(7-5(2x+11))=0

We multiply parentheses

2x-(7-5(2x+11))-10=0



We calculate terms in parentheses: -(7-5(2x+11)), so:

7-5(2x+11)

determiningTheFunctionDomain
-5(2x+11)+7

We multiply parentheses

-10x-55+7

We add all the numbers together, and all the variables

-10x-48

Back to the equation:

-(-10x-48)



We get rid of parentheses

2x+10x+48-10=0

We add all the numbers together, and all the variables

12x+38=0

We move all terms containing x to the left, all other terms to the right

12x=-38

x=-38/12

x=-3+1/6

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