2(x-5)=7x-(4-x)

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Solution for 2(x-5)=7x-(4-x) equation: 



2(x-5)=7x-(4-x)

We move all terms to the left:

2(x-5)-(7x-(4-x))=0

We add all the numbers together, and all the variables

2(x-5)-(7x-(-1x+4))=0

We multiply parentheses

2x-(7x-(-1x+4))-10=0



We calculate terms in parentheses: -(7x-(-1x+4)), so:

7x-(-1x+4)

We get rid of parentheses

7x+1x-4

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

2x-8x+4-10=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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