2(x-5)=8x+3(x-4)

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Solution for 2(x-5)=8x+3(x-4) equation: 



2(x-5)=8x+3(x-4)

We move all terms to the left:

2(x-5)-(8x+3(x-4))=0

We multiply parentheses

2x-(8x+3(x-4))-10=0



We calculate terms in parentheses: -(8x+3(x-4)), so:

8x+3(x-4)

We multiply parentheses

8x+3x-12

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We get rid of parentheses

2x-11x+12-10=0

We add all the numbers together, and all the variables

-9x+2=0

We move all terms containing x to the left, all other terms to the right

-9x=-2

x=-2/-9

x=2/9

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