2(x-5)=8x+3(x-4)

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Solution for 2(x-5)=8x+3(x-4) equation:



2(x-5)=8x+3(x-4)
We move all terms to the left:
2(x-5)-(8x+3(x-4))=0
We multiply parentheses
2x-(8x+3(x-4))-10=0
We calculate terms in parentheses: -(8x+3(x-4)), so:
8x+3(x-4)
We multiply parentheses
8x+3x-12
We add all the numbers together, and all the variables
11x-12
Back to the equation:
-(11x-12)
We get rid of parentheses
2x-11x+12-10=0
We add all the numbers together, and all the variables
-9x+2=0
We move all terms containing x to the left, all other terms to the right
-9x=-2
x=-2/-9
x=2/9

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