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2(x-5)=x+12+3x
We move all terms to the left:
2(x-5)-(x+12+3x)=0
We add all the numbers together, and all the variables
2(x-5)-(4x+12)=0
We multiply parentheses
2x-(4x+12)-10=0
We get rid of parentheses
2x-4x-12-10=0
We add all the numbers together, and all the variables
-2x-22=0
We move all terms containing x to the left, all other terms to the right
-2x=22
x=22/-2
x=-11
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