2(x-5)=x+40/3

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Solution for 2(x-5)=x+40/3 equation: 



2(x-5)=x+40/3

We move all terms to the left:

2(x-5)-(x+40/3)=0

We add all the numbers together, and all the variables

2(x-5)-(+x+40/3)=0

We multiply parentheses

2x-(+x+40/3)-10=0

We get rid of parentheses

2x-x-10-40/3=0

We multiply all the terms by the denominator


2x*3-x*3-40-10*3=0

We add all the numbers together, and all the variables

2x*3-x*3-70=0

Wy multiply elements

6x-3x-70=0

We add all the numbers together, and all the variables

3x-70=0

We move all terms containing x to the left, all other terms to the right

3x=70

x=70/3

x=23+1/3

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