2(x-5+3)+2x=10-8(x+2)

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Solution for 2(x-5+3)+2x=10-8(x+2) equation: 



2(x-5+3)+2x=10-8(x+2)

We move all terms to the left:

2(x-5+3)+2x-(10-8(x+2))=0

We add all the numbers together, and all the variables

2(x-2)+2x-(10-8(x+2))=0

We add all the numbers together, and all the variables

2x+2(x-2)-(10-8(x+2))=0

We multiply parentheses

2x+2x-(10-8(x+2))-4=0



We calculate terms in parentheses: -(10-8(x+2)), so:

10-8(x+2)

determiningTheFunctionDomain
-8(x+2)+10

We multiply parentheses

-8x-16+10

We add all the numbers together, and all the variables

-8x-6

Back to the equation:

-(-8x-6)



We add all the numbers together, and all the variables

4x-(-8x-6)-4=0

We get rid of parentheses

4x+8x+6-4=0

We add all the numbers together, and all the variables

12x+2=0

We move all terms containing x to the left, all other terms to the right

12x=-2

x=-2/12

x=-1/6

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