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2(x-6)-3=5x-3(x+4)
We move all terms to the left:
2(x-6)-3-(5x-3(x+4))=0
We multiply parentheses
2x-(5x-3(x+4))-12-3=0
We calculate terms in parentheses: -(5x-3(x+4)), so:We add all the numbers together, and all the variables
5x-3(x+4)
We multiply parentheses
5x-3x-12
We add all the numbers together, and all the variables
2x-12
Back to the equation:
-(2x-12)
2x-(2x-12)-15=0
We get rid of parentheses
2x-2x+12-15=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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