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2(x-6)-5(x-3)=6(x+8)
We move all terms to the left:
2(x-6)-5(x-3)-(6(x+8))=0
We multiply parentheses
2x-5x-(6(x+8))-12+15=0
We calculate terms in parentheses: -(6(x+8)), so:We add all the numbers together, and all the variables
6(x+8)
We multiply parentheses
6x+48
Back to the equation:
-(6x+48)
-3x-(6x+48)+3=0
We get rid of parentheses
-3x-6x-48+3=0
We add all the numbers together, and all the variables
-9x-45=0
We move all terms containing x to the left, all other terms to the right
-9x=45
x=45/-9
x=-5
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