2(x-6)=3(x+1)-27

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Solution for 2(x-6)=3(x+1)-27 equation: 



2(x-6)=3(x+1)-27

We move all terms to the left:

2(x-6)-(3(x+1)-27)=0

We multiply parentheses

2x-(3(x+1)-27)-12=0



We calculate terms in parentheses: -(3(x+1)-27), so:

3(x+1)-27

We multiply parentheses

3x+3-27

We add all the numbers together, and all the variables

3x-24

Back to the equation:

-(3x-24)



We get rid of parentheses

2x-3x+24-12=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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