2(x-6)=3(x-4)-4

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Solution for 2(x-6)=3(x-4)-4 equation: 



2(x-6)=3(x-4)-4

We move all terms to the left:

2(x-6)-(3(x-4)-4)=0

We multiply parentheses

2x-(3(x-4)-4)-12=0



We calculate terms in parentheses: -(3(x-4)-4), so:

3(x-4)-4

We multiply parentheses

3x-12-4

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)



We get rid of parentheses

2x-3x+16-12=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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