2(x-7)-8(x-4)=-7x+11

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Solution for 2(x-7)-8(x-4)=-7x+11 equation: 



2(x-7)-8(x-4)=-7x+11

We move all terms to the left:

2(x-7)-8(x-4)-(-7x+11)=0

We multiply parentheses

2x-8x-(-7x+11)-14+32=0

We get rid of parentheses

2x-8x+7x-11-14+32=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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