2(x-8)+2x=4(x+3)-28

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Solution for 2(x-8)+2x=4(x+3)-28 equation: 



2(x-8)+2x=4(x+3)-28

We move all terms to the left:

2(x-8)+2x-(4(x+3)-28)=0

We add all the numbers together, and all the variables

2x+2(x-8)-(4(x+3)-28)=0

We multiply parentheses

2x+2x-(4(x+3)-28)-16=0



We calculate terms in parentheses: -(4(x+3)-28), so:

4(x+3)-28

We multiply parentheses

4x+12-28

We add all the numbers together, and all the variables

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

4x-(4x-16)-16=0

We get rid of parentheses

4x-4x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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