2(x-8)+2x=4(x+4)-32

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Solution for 2(x-8)+2x=4(x+4)-32 equation: 


Simplifying
2(x + -8) + 2x = 4(x + 4) + -32

Reorder the terms:
2(-8 + x) + 2x = 4(x + 4) + -32
(-8 * 2 + x * 2) + 2x = 4(x + 4) + -32
(-16 + 2x) + 2x = 4(x + 4) + -32

Combine like terms: 2x + 2x = 4x
-16 + 4x = 4(x + 4) + -32

Reorder the terms:
-16 + 4x = 4(4 + x) + -32
-16 + 4x = (4 * 4 + x * 4) + -32
-16 + 4x = (16 + 4x) + -32

Reorder the terms:
-16 + 4x = 16 + -32 + 4x

Combine like terms: 16 + -32 = -16
-16 + 4x = -16 + 4x

Add '16' to each side of the equation.
-16 + 16 + 4x = -16 + 16 + 4x

Combine like terms: -16 + 16 = 0
0 + 4x = -16 + 16 + 4x
4x = -16 + 16 + 4x

Combine like terms: -16 + 16 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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