2(x-8)-5=9(x+2)+1

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Solution for 2(x-8)-5=9(x+2)+1 equation: 



2(x-8)-5=9(x+2)+1

We move all terms to the left:

2(x-8)-5-(9(x+2)+1)=0

We multiply parentheses

2x-(9(x+2)+1)-16-5=0



We calculate terms in parentheses: -(9(x+2)+1), so:

9(x+2)+1

We multiply parentheses

9x+18+1

We add all the numbers together, and all the variables

9x+19

Back to the equation:

-(9x+19)



We add all the numbers together, and all the variables

2x-(9x+19)-21=0

We get rid of parentheses

2x-9x-19-21=0

We add all the numbers together, and all the variables

-7x-40=0

We move all terms containing x to the left, all other terms to the right

-7x=40

x=40/-7

x=-5+5/7

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