2(x-8)=3(x-2)+10

Solution for 2(x-8)=3(x-2)+10 equation:

2(x-8)=3(x-2)+10

We move all terms to the left:

2(x-8)-(3(x-2)+10)=0

We multiply parentheses

2x-(3(x-2)+10)-16=0


We calculate terms in parentheses: -(3(x-2)+10), so:

3(x-2)+10

We multiply parentheses

3x-6+10

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)


We get rid of parentheses

2x-3x-4-16=0

We add all the numbers together, and all the variables

-1x-20=0

We move all terms containing x to the left, all other terms to the right

-x=20

x=20/-1

x=-20