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2(x-9)=50-3(10x+1)
We move all terms to the left:
2(x-9)-(50-3(10x+1))=0
We multiply parentheses
2x-(50-3(10x+1))-18=0
We calculate terms in parentheses: -(50-3(10x+1)), so:We get rid of parentheses
50-3(10x+1)
determiningTheFunctionDomain -3(10x+1)+50
We multiply parentheses
-30x-3+50
We add all the numbers together, and all the variables
-30x+47
Back to the equation:
-(-30x+47)
2x+30x-47-18=0
We add all the numbers together, and all the variables
32x-65=0
We move all terms containing x to the left, all other terms to the right
32x=65
x=65/32
x=2+1/32
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