2(x/3+x)=40

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Solution for 2(x/3+x)=40 equation: 



2(x/3+x)=40

We move all terms to the left:

2(x/3+x)-(40)=0



Domain of the equation: 3+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

2(+x+x/3)-40=0

We multiply parentheses

2x+2x-40=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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