If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2(x2)=10
We move all terms to the left:
2(x2)-(10)=0
We add all the numbers together, and all the variables
2x^2-10=0
a = 2; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·2·(-10)
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*2}=\frac{0-4\sqrt{5}}{4} =-\frac{4\sqrt{5}}{4} =-\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*2}=\frac{0+4\sqrt{5}}{4} =\frac{4\sqrt{5}}{4} =\sqrt{5} $
| 9(x+4)=1+-5 | | X^2-16x-258=0 | | 4(7x-5)=150 | | 9(w+2)=5w-24 | | 4(q−98)=8 | | 295=14-y | | t/5-4=6 | | 3m+5=-8m-7 | | 5(4+2x)=9(x-1) | | 9(3+4)=2+2x | | 13=m/4+10 | | 5/6w+21=-1/3(2w-9 | | 23x-5+24x+5=180 | | 13=m/4+ 10 | | -2=3v+4 | | 7x+9)-4=8(x-9) | | 3v-9=2v=7-v | | (2)(0.25z)=(2)(z-5) | | 1=w/4-17 | | s2+ 12=15 | | 3x–10=-1 | | 146-y=198 | | 9(5/3)=x | | 3v-9=2v+7-v | | 12-3a-3=a-5a | | 5x-83x=12 | | 6.2+u/5=-6.3 | | 1/5x+15=6 | | u/2+7=3 | | 5d2-13d+7=0 | | 3v+15=63 | | -8+5v=-23 |