2(x2+1)=x2-3

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Solution for 2(x2+1)=x2-3 equation: 



2(x2+1)=x2-3

We move all terms to the left:

2(x2+1)-(x2-3)=0

We add all the numbers together, and all the variables

2(+x^2+1)-(+x^2-3)=0

We multiply parentheses

2x^2-(+x^2-3)+2=0

We get rid of parentheses

2x^2-x^2+3+2=0

We add all the numbers together, and all the variables

x^2+5=0

a = 1; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·1·5
Δ = -20
Delta is less than zero, so there is no solution for the equation

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