2(x2+3)-1-2x=x+5

Solution for 2(x2+3)-1-2x=x+5 equation:

2(x2+3)-1-2x=x+5

We move all terms to the left:

2(x2+3)-1-2x-(x+5)=0

We add all the numbers together, and all the variables

2(+x^2+3)-2x-(x+5)-1=0

We multiply parentheses

2x^2-2x-(x+5)+6-1=0

We get rid of parentheses

2x^2-2x-x-5+6-1=0

We add all the numbers together, and all the variables

2x^2-3x=0

a = 2; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·2·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*2}=\frac{6}{4}
=1+1/2
$