2(x2+3)=-6(x+9)

Solution for 2(x2+3)=-6(x+9) equation:

2(x2+3)=-6(x+9)

We move all terms to the left:

2(x2+3)-(-6(x+9))=0

We add all the numbers together, and all the variables

2(+x^2+3)-(-6(x+9))=0

We multiply parentheses

2x^2-(-6(x+9))+6=0


We calculate terms in parentheses: -(-6(x+9)), so:

-6(x+9)

We multiply parentheses

-6x-54

Back to the equation:

-(-6x-54)


We get rid of parentheses

2x^2+6x+54+6=0

We add all the numbers together, and all the variables

2x^2+6x+60=0

a = 2; b = 6; c = +60;
Δ = b2-4ac
Δ = 62-4·2·60
Δ = -444
Delta is less than zero, so there is no solution for the equation