2(x2+x)=x+1

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Solution for 2(x2+x)=x+1 equation:



2(x2+x)=x+1
We move all terms to the left:
2(x2+x)-(x+1)=0
We add all the numbers together, and all the variables
2(+x^2+x)-(x+1)=0
We multiply parentheses
2x^2+2x-(x+1)=0
We get rid of parentheses
2x^2+2x-x-1=0
We add all the numbers together, and all the variables
2x^2+x-1=0
a = 2; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·2·(-1)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*2}=\frac{-4}{4} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*2}=\frac{2}{4} =1/2 $

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