2(x2-1)+3x=4x2-x

Solution for 2(x2-1)+3x=4x2-x equation:

2(x2-1)+3x=4x^2-x

We move all terms to the left:

2(x2-1)+3x-(4x^2-x)=0

We add all the numbers together, and all the variables

2(+x^2-1)+3x-(4x^2-x)=0

We multiply parentheses

2x^2+3x-(4x^2-x)-2=0

We get rid of parentheses

2x^2-4x^2+3x+x-2=0

We add all the numbers together, and all the variables

-2x^2+4x-2=0

a = -2; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{-4}=1$