2(xx2+x+3)=8(x-1)+2xx2

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Solution for 2(xx2+x+3)=8(x-1)+2xx2 equation: 



2(xx2+x+3)=8(x-1)+2xx2

We move all terms to the left:

2(xx2+x+3)-(8(x-1)+2xx2)=0

We add all the numbers together, and all the variables

2(x+xx2+3)-(8(x-1)+2xx2)=0

We multiply parentheses

2x+2x-(8(x-1)+2xx2)+6=0



We calculate terms in parentheses: -(8(x-1)+2xx2), so:

8(x-1)+2xx2

We multiply parentheses

8x+2xx2-8

Back to the equation:

-(8x+2xx2-8)



We add all the numbers together, and all the variables

4x-(8x+2xx2-8)+6=0

We get rid of parentheses

4x-8x-2xx2+8+6=0

We add all the numbers together, and all the variables

-4x-2xx2+14=0

We move all terms containing x to the left, all other terms to the right

-4x-2xx2=-14

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