2(y)+3/y=7

Solution for 2(y)+3/y=7 equation:

2(y)+3/y=7

We move all terms to the left:

2(y)+3/y-(7)=0


Domain of the equation: y!=0

y∈R


We multiply all the terms by the denominator


2y*y-7*y+3=0

We add all the numbers together, and all the variables

-7y+2y*y+3=0

Wy multiply elements

2y^2-7y+3=0

a = 2; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·2·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*2}=\frac{2}{4}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*2}=\frac{12}{4}
=3
$