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2(y+1)(y-1)-y=2y-7
We move all terms to the left:
2(y+1)(y-1)-y-(2y-7)=0
We add all the numbers together, and all the variables
-1y+2(y+1)(y-1)-(2y-7)=0
We use the square of the difference formula
y^2-1y-(2y-7)-1=0
We get rid of parentheses
y^2-1y-2y+7-1=0
We add all the numbers together, and all the variables
y^2-3y+6=0
a = 1; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·1·6
Δ = -15
Delta is less than zero, so there is no solution for the equation
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